Is it possible to burn a 773 MB video file onto a 700 MB disc? I can't find a guide on this site. Thanks in advance.
yes ican get 776mb by using discjuggler on over burn if you have not got discjuggler im not to sure where to get it now
DiscJUggler alone is not enough to overburn 773 megs, you will also need media that supports it as well. BTW, Nero can also overburn. You can purcahse 99 minute (870 megs) discs here. http://www.meritline.com/cdr-cd-r-blank-media-disc-disk-bulk-discs-disks.html
Whoa we all forgot to note the important one important piece of information: are you trying to burn a (S)VCD? If so then it is SUPPOSED to be that big. I have a more complete set of Q&A here: http://www.hazza.dsl.pipex.com/faq.htm#OVERBURN You should be ok to burn on 700MB media
No, I'm not trying to burn a SVCD, just a regular .avi file. So it is not possible to overburn in on just a 700mb cd? Would the easist way to reduce file size to be just to cut parts from it then?
You wont be able to overburn by that much. There are a couple ways to work around this and I've outlined them here: http://www.hazza.dsl.pipex.com/faq.htm#CLIPAVI
Avoid overburning, this is useful only when if the side of what you're burning is slightly larger than the standard size of the CD [bold]and[/bold] if your burner allows it. If the file were an [bold]image[/bold] (e.g. .CUE/.BIN, .BWA, .CCD, .ISO, .MDS, .NRG, and so on) the right dimension for a CD to contain it would have been this: Size Max = [bold]D[/bold]*2352/2048 Size Max is the max size of the image you want to burn into the CD and [bold]D[/bold] is the dimension of the CD, calculated as if 1 CD sector = 2048 bytes and which is, by default, the one shown in the cover (e.g. 74' or 650 MB, 80' or 700 MB). A standard 74 min CD contains 333,000 sectors and a standard 80 min CD contains 360,000 sectors. 1 sector contains much stuff depending on the type of CD you're writing. The burner itself 'puts' into the CD the Error Detection Codes (EDC) and the Error Corrections Codes (ECC). This stuff is HUGE for Data CDs (e.g. simple files burned on a CD), medium for videos [e.g. (S)VCDs] (2336 bytes/sector are free), zero for audio (e.g. standard audio CDs: all 2352 bytes/sector are free). Therefore, on a 74 min CD you can fit very large RAW images, up to 333,000 x 2352 = 783,216,000 bytes (747 Mb). This should be the upper limit for a RAW image created from a 74 min CD. Remember that if you store standard data (backup files), you can burn only 333,000 x 2048 = 681,984,000 bytes (the well known 650 MB limit). 'Images' copy EVERYTHING is on the disk, so the maximum size (2352 x sectors number) is achieved when you 'extract' an image ('perfect' copy of a disc). In your case, you have an .AVI. If you simply 'backup' the .AVI you need exactly a CD '773 MB large'. If you build, for instance, a VCD (e.g. with TMPGenc to convert .AVI->.MPG plus VCDEasy to build the a (S)VCD with the .MPG, which now should have a size depending on the type (VCD, SVCD) of the Video CD you're building and the length of the movie, people may use VCDgear but I dont' know it) you need: D=773*2048/2336 = 87.6% 773 MB = 678 MB!!! Got it? There is a clear 'sticky' thread here: http://forums.afterdawn.com/thread_view.cfm/7976 [bold]BIN / .CUE / .ISO Frequently asked questions. READ1ST[/bold]: exactly at point 7) (I wrote it about 2 years ago, sorry for doing this self-advertisement). Sorry. Since you seem to just want to 'backup' your .AVI using data CDs, I can only suggest you to compress it with, e.g., [bold]WinRAR[/bold], splitting it into two smaller files (press '[bold]add[/bold]', get your file, choose, e.g. 'compression method: [bold]best[/bold]' and 'Split to volumes, bites: [bold]700,000[/bold]'). This is the best you can do (alas, you're requesting too much!!). _ _X_X_X_X_X_[small]Read forum rules! http://forums.afterdawn.com/thread_view.cfm/2487[/small]
